Point O is the center of the circle. What is the value of x?
PQ is tangent to oo at P.

x = 15

Step-by-step explanation:

Since PQ is a tangent then ∠ OPQ is a right angle, that is the angle between a tangent and the radius at the point of contact.

Thus Δ OPQ is right with hypotenuse = 9 + 8 = 17

Using Pythagoras' identity in the right triangle, then

x² + 8² = 17²

x² + 64 = 289 ( subtract 64 from both sides )

x² = 225 ( take the square root of both sides )

x = = 15

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000