A and b are positive integers and a−b = 2. Evaluate the following:

27^(1/3b)/9^(1/2a)

9^(1/2b)/3^a

1/9

Step-by-step explanation:

a - b = 2

27^(1/3b)/9^(1/2a)

so...b = a - 2

27^( (1/3)  b ) / 9^((1/2) a )

= (3^3)(1/3b)   over  (3^2)^(1/2a)

= 3^b   over 3^a =    3^ (b - a) =  3^(-2) =  1/9

9^(1/2b)/3^a =  (9^(1/2))^b  / 3^a  =  3^b  / 3^a =   3^(b -a) = 3^-2 = 1/9

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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