Question 4 (5 points)
The sum of two consecutive odd integers is 56.
What is the smaller number?

A.25
B.27
C.29
D.31

B

Step-by-step explanation:

note there is a difference of 2 between consecutive odd integers.

let the 2 integers be n and n + 2, then

n + n + 2 = 56, that is

2n + 2 = 56 ( subtract 2 from both sides )

2n = 54 ( divide both sides by 2 )

n = 27

Thus the smaller integer is 27 → B

The larger integer is n + 2 = 27 + 2 = 29

(c, 0) i might be wrong so don't put full faith on my answer

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584