Will mark brainliest‼️Students create a standing wave
with three loops on a slinky 3.75 m
long. They time 20 oscillations in
6.73 s. What is the velocity of the
waves in the string?
(Unit = m/s)

The velocity of the wave in the string is 7.43m/s

Step-by-step explanation:

Step 1:

Data obtained from the question.

Length (L) = 3.75m

Number of oscillation (n) = 20

Time (t) = 6.73 secs

Step 2:

Determination of the wavelength of the wave. This is illustrated below:

Since the wave made three (3) loops, the length is given by:

L = 3λ/2

L is the length

λ is the wavelength

Thus, we can obtain the wavelength (λ) as follow:

From the question,

Length (L) = 3.75m

Wavelength (λ) =?

L = 3λ/2

3.75 = 3λ/2

Cross multiply to express in linear form

3λ = 3.75 x 2

Divide both side by the 3

λ = (3.75 x 2)/3

λ = 2.5m

Step 3:

Determination of the frequency of the wave. This is illustrated below:

The frequency is the number of oscillations made in 1 second. Thus it can be represented mathematically as:

Frequency (f) = number of oscillation (n)/ time (t)

f = n/t

Number of oscillation (n) = 20

Time (t) = 6.73 secs

Frequency (f) =?

f = n/t

f = 20/6.73

f = 2.97s^-1

Step 4:

Determination of the velocity of the wave.

Velocity is related to the wavelength and frequency by the following equation:

Velocity = wavelength x frequency

V = λf

Wavelength (λ) = 2.5m

Frequency (f) = 2.97s^-1

Velocity (V) =?

V = λf

V = 2.5 x 2.97

V = 7.43m/s

Therefore, the velocity of the wave in the string is 7.43m/s

570, the answer is 570, hope it

i suppose it should be (y=2x-5)

step-by-step explanation: