What are the solutions to the equation and check for extraneous solutions:

16=(x-2)^2/3

we have  x = -62 or x = 66

Step-by-step explanation:

16=(x-2)^2/3

I would take square root first

4 =  (x - 2)^ (1/3)

or   -4  =  (x - 2)^(1/3)

4^3  =  x - 2

64 = x - 2

x = 66

or  -4 ^3 = x - 2

-64 = x - 2

x = -62

we have  x = -62 or x = 66

this is false ^.^ lol

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol