A survey of n = 100 students found that 28 of them were majoring in a STEM field. Give a 95% confidence interval estimate for the true proportion, p, of students who major in a STEM field.

We are 95% that the true proportion of interest for the students were majoring in a STEM field is between 0.192 and 0.368

Step-by-step explanation:

We want to calculate a confidence interval for the true proportion p who represent the % of students were majoring in a STEM field. The best point of estimate for this proportion is given by:

The confidence interval for the true proportion of interest is given by:  

Since the confidence level is 95%, the significance level would be and . The critical values for this case are:

And after replace into the formula we got:

We are 95% that the true proportion of interest for the students were majoring in a STEM field is between 0.192 and 0.368

898.1666667

step-by-step explanation:

5389/6 = 898.1666667