What is the value of i = 1

Step-by-step explanation:

hello : let : S this sum : S =4×(1/2)^(1-1)+4×(1/2)^(2-1)+4×(1/2)^(3-1)

S= 4×(1/2)^(0)+4×(1/2)^(1)+4×(1/2)^(2)

but :  (1/2)^(0)= 1

        (1/2)^(1) = 1/2

        (1/2)^(2)=  1/4

so : S= 4×1 +4×(1/2)+4×(1/4) = 4+2+1 = 6