Simplify the expression (2x^2+6x−7)−(3x^2+3x−1)+(x−8)

= - x^2 + 4x  - 14

Step-by-step explanation:

(2x^2+6x−7)−(3x^2+3x−1)+(x−8)

= (2x^2+6x−7   )    −3x^2   -3x  +1     +   (x−8)

= (2x^2+6x−7   )    −3x^2   -3x  +1     +   x−8

= (2x^2+6x−7   )    −3x^2   -2x - 7

= 2x^2+6x−7       −3x^2   -2x - 7

= 2x^2+6x−7       −3x^2   -2x - 7

= - x^2 + 4x  - 14

da freeck kinda math is this just drop out

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.