so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre
so in quadrilateral oabc
< coa + < oab + < ocb + < abc = 360
150 +90+90 + < abc = 360
330 + < abc = 360
< abc = 360 -330 = 30
so < abc = 30
⭐dhruv⭐
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