Segment AB has point A located at (4, 2). If the distance from A to B is 3 units, which of the following could be used to calculate the coordinates for point B?

3 = square root of the quantity of x minus 2 all squared plus y minus 4 all squared
3 = square root of the quantity of x minus 4 all squared plus y minus 2 all squared
3 = square root of the quantity of x plus 2 all squared plus y plus 4 all squared
3 = square root of the quantity of x plus 4 all squared plus y plus 2 all squared

where is the gragh

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.