Three national news networks are trying to estimate what percentage of
American voters support a particular presidential candidate. To estimate the
population parameter, each of the three networks collects data from a simple
random sample of voters. Here are the numbers of voters in the networks
random samples:
• Network A: 2250 voters sampled
• Network B: 2800 voters sampled
• Network C: 2500 voters sampled
Which sample is likely to have the least variability?
O
A. The Network A sample
OB. The Network B sample
O
C. The Network C sample
Activ

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0

47 - 90 = 43

43 - 180 = x

x = 137

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;