Alvin has a prism-like water tank whose base area is 0.90.90, point, 9 square meters and height is 0.60.60, point, 6 meters. He wants to buy guppy fish, and the pet store owner tells him to make sure their density in the tank isn't more than 555 fish per cubic meter How many fish can Alvin get, at most?

2 Fishes

Step-by-step explanation:

Base Area of the Tank=0.9 square meters

Height of the Tank =0.6 meters

Volume of a Prism=Base Area X Height

Therefore, the volume of the tank=0.9 X 0.6=0.54 cubic meters

Now, the density must not exceed 5 fish per cubic meter.

We also know that:

Density=Mass ÷ volume

Therefore:

5=Number of Fishes÷0.54

Number of Fishes= 5 X 0.54 =2.7 fishes

Alvin can get 2 fishes at most

step-by-step explanation:

1. the cylinder is a. 54

2.   a.108 /

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i