A plane is cruising at an altitude of 30,000 feet.
What is the distance, to the nearest mile, from
the plane to the horizon? *
(5 Points)
4000
c mi

Correct option: Third one: 213 mi

Step-by-step explanation:

The distance from the plane to the horizon is the segment EH in the figure.

The altitude of the plane is 30,000 feet, which is equal to 5.6818 miles, and that is the value of the segment ED.

The segment DC is equal segment CH, as they are the radius of the circle.

So know, to solve this problem, we can use Pythagoras' equation:

EC^2 = CH^2 + EH^2

(5.6818+4000)^2 = 4000^2 + EH^2

EH^2 = 4005.6818^2 - 4000^2

EH^2 = 45486.6828

EH = 213.2761 miles

Rounding to nearest mile, we have EH = 213 miles

Correct option: Third one.

i believe the answer is letter c) 8

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length