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Solve the equation for all real solutions in simplest form:
4n^2-19n+18=0

n=3.4, n=1.3

Step-by-step explanation:

4n^2-19n+18=0

solve using quadratic formula

a=4, b=-19, c=18

n=-(-19)±√(-19)^2-4·4·18/2·4

(solve using calulator or PEMDAS)

(solve for both + and -)

n=3.4, n=1.3

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b