At Sports Shoe Warehouse, the cost of 11 pairs of soccer shoes is $1100 plus $66 for each additional pair. From Winning Team Shoes, the cost of 11 pairs of soccer shoes is $825 plus an additional 6% for each additional pair. For how many total pairs of soccer shoes does each vendor cost about the same? Write the equations

The cost of the stores will be the same when "-6" pair of shoes are bought, therefore they will never be the same in real world applications.

Step-by-step explanation:

In order to solve this problem we will create equations for each store, where "s" is the total number of shoe pairs that were bought.

For the store A:

total cost = 1100 + 66*(s - 11)

total cost = 1100 + 66*s -726

total cost = 374 + 66*s

For the store B:

total cost = 825 + 825*0.06*(s-11)

total cost = 825 + 49.5(s -11)

total cost = 825 + 49.5*s -544.5

total cost = 49.5*s +280.5

In order for the cost to be the same, the expressions must be equal, therefore:

374 + 66*s = 49.5*s +280.5

66*s - 49.5*s = 280.5 - 374

15.5*s = -93.5

s = -6.03

Since the value for pair of shoes is negative, this means that the cost for each vendors will never be the same.

college

27 +27 or 27times 2=54

the diffrence is 0