Five automobiles of the same type are to be driven on a 300-mile trip. The first two will use an economy brand of gasoline, and the other three will use a name brand. Let X1,X2,X3,X4, and X5 be the observed fuel efficiencies (mpg) for the five cars. Suppose these variables are independently distributed with µ1 = µ2 = 20, µ3 = µ4 = µ5 = 24, and σ1 = σ2 = 4 for the economy brand. Define a random variable Y by

Y = (X1 + X2)/2 - (X3 + X4 + X5) / 3,

so that Y is a measure of the difference in efficiency between economy gas and premium gas. Compute P(0 <= Y) and P(-1 <= Y <= 1). [Hint: write Y = c1X1 + ... +c5X5.]

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

need points to ask question

step-by-step explanation: