7x-3
6x-7
Find an equation of the tangent line to the curve of y =
(1, 3).
at the point

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

idk idk idk idk idk

step-by-step explanation:

570, the answer is 570, hope it