What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
A. (-6, 3)
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Mathematics, 05.05.2020 10:05 hellokitty1647
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
A. (-6, 3)
B. (-3, 6)
C. (3, -6)
D. (6, -3)
Answers: 2
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