The number of sit-ups Micah does is the sum of twice a number and 25. The number of sit-ups Micah does is also 3 times the number minus 25. How
many sit-ups does Micah do? (hint: set up two equations, then solve for each variable)

125

Step-by-step explanation:

Let the number represented in the question be b.

Let the number of situps be also represented by z.

The number of sit-ups Micah does is the sum of twice a number and 25. This means:

z = (2×b) + 25

z = 2b + 25 equation i

The number of sit-ups Micah does is also 3 times the number minus 25. This means:

z = (3×b) - 25

z = 3b - 25 equation ii

Equate equation I and ii together.

2b + 25 = 3b - 25

Collect like terms

3b - 2b = 25 + 25

b = 50

Put the value of back into equation I

z = 2b + 25

z = (2×50) + 25

z = 100 + 25

z = 125

The number of situps is 125.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.