The measure of one side of a square is (x + 4). What is the difference of the area of the square and the
perimeter of the square?
a. 2(x+4)
b. x(x +4)
C. 2x+4

(A) 2(x + 4)

Step-by-step explanation: We know that the measure of one side of the square is (x + 4). But, we first will need to find the total area and perimeter of the square in order to find the difference between them.

The area is length x width, so multiply 2(x + 4) Since all the sides are the same.

2(x + 4) = 2x + 8. The area is 2x + 8.

To find the perimeter simply add x + 4, four times. 4(x + 4).

4(x + 4) = 4x + 16 as the total perimeter of the square.

Now subtract the area from the perimeter.

4x + 16 - (2x + 8)    --Distribute negative sign.

4x + 16 - 2x - 8        --Combine like terms

4x - 2x + 16 - 8

2x + 8.

2(x + 4) is equivalent to 2x + 8 and is therefore the answer.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

step-by-step explanation: