A wheel with a diameter of 25 in. is in a puddle of water 8.1 in. deep. What is the width of the wheel, AB, at the surface of the water?

Please actually answer the question <3

The length AB is 23.4in

Step-by-step explanation:

N/B please see the attached detailed diagram for your reference and better understanding

This problem bothers on the mensuration of flat shapes.

The width AB is the chord of the wheel

The radius of the whee r= 25/2= 12.5in

The depth of the wheel in the puddle is 8.1in

Let b be the distance from the surface AB to the diameter

b= 12.5-8.1  = 4.4in

Applying the formula

Chord Length = 2 *√(r²-b²)

=2*√(12.5²-4.4²)

= 2*√(156.25-19.36)

=2*√(136.89

=2*11.7

=23.4in

won't that be plagrisim thought?

step-by-step explanation:

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a