A wheel with a diameter of 25 in. is in a puddle of water 8.1 in. deep. What is the width of the wheel, AB, at the surface of the water?

AB = 23.4 inches

Step-by-step explanation:

If the diameter of the wheel is 25 inches, we have that its radius is 25/2 = 12.5 inches.

If we draw a radius to the bottom of the wheel and a radius to point A, we have a triangle where we can use Pythagoras' formula:

(see image attached for better understanding)

r^2 = (r-8.1)^2 + (AB/2)^2

12.5^2 = 4.4^2 + AB^2/4

156.25 = 19.36 + AB^2/4

AB^2/4 = 136.89

AB^2 = 547.56

AB = 23.4 inches

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3