Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the
solution is made up of a 20% acid solution. The remaining three-quarters is made up of a solution of unknown
concentration, c.
Which equation can be used to determine c, the unknown concentration?
6 30c + 10(0.2) = 40(0.32)
02()+ . (0.2) = 40(0.32)
O
(C)
(0.2)) = 40(0.32)
O 30(c)(10(0.2)) = 40(0.32)

Let

x = amount of 20% solution used (mL)

y = amount of solution used with unknown concentration (also mL)

c = the unknown concentration (%)

There are 40 mL of the new solution, so

x + y = 40

We use 10 mL of the 20% solution, so x = 10.

Each mL of either solution contributes c/100 mL of acid. So if 1/4 of the new solution (which is 10 mL) is made from the 20% solution, then this solution contributes

(20/100) * (10 mL) = 2 mL

of acid to the new one.

The new solution has a concentration of 32% acid, meaning it contains

(32/100) * (40 mL) = 12.8 mL

of acid. This means (12.8 - 2) mL = 10.8 mL of acid are provided by the second solution of unknown concentration.

We used 30 mL of the unknown solution, so the concentration is c such that

(c/100) * (30 mL) = 10.8 mL  ==>  c = 36

Putting everything together, we found c by setting up the equation

0.2 * 10 + c/100 * 30= 0.32 * 40

From your given options, pick whatever is equivalent. It's hard to tell what each option is, so I'll leave it to you.

dont think so

step-by-step explanation:

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8