In ΔCAB, if m∠A = 10x + 9, m∠B = 34°, and m∠C = 97°, what is the value of x?

triangle CAB, point E is on segment AC between points A and C and point D is on segment BC between points B and C, creating segment ED

x = 2
x = 3
x = 4
x = 5

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)