I will mark brainliest whoever answers first, please I really need help.

You are conducting a significance test of H0: μ = 5 against Ha: μ > 5. After checking the conditions are met from a simple random sample of 30 observations, you obtain t = 2.35. Based on this result, describe the p-value. (4 points)

Group of answer choices

The p-value falls between 0.15 and 0.2.

The p-value falls between 0.025 and 0.05.

The p-value falls between 0.01 and 0.02.

The p-value falls between 0.005 and 0.01.

The p-value is less than 0.005.

Step-by-step explanation:

Since the number of samples is given as n = 30, we would determine the degree of freedom, df

df = n - 1 = 30 - 1

df = 29

Since the test statistic is given as 2.35 and the df = 29, we would determine the p value from the t distribution table. We will look for the row containing df = 29 and trace the two columns between which 2.35 falls. The result would also be in the row containing one tailed test. Therefore, the p-value falls between 0.025 and 0.01.

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb