Tyra has 38 counters. She now puts the 38 counters into some bags so that Each bag has an equal number. There are no counters left over. There are more than 10 counters in each bag. Work out the number of bags and number of counters in each bag.

I mean, you can divide the counters by the range 2 - 38.

I only managed to find out that 38 ÷ 2 = 19.

And 38 ÷ 19 = 2.

It says that there are more than 10 counters in each bag.

So 2 bags is the most liable option.

There are 2 bags and 19 counters in each bag.

2 bags, 19 counters.

Step-by-step explanation:

This question is looking for factors of 38 with counters being a factor greater ten and the number of bags being the factor that multiplies the counters to get 38. First, find the factors of 38.

1 x 38 = 38

2 x 19 = 38

Since the problem says bags with an s, we can know that there has to be more than one bag. That leaves us with 2 x 19.

your answer is a

step-by-step explanation:

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option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.