What is the numerical solution to the
statement below?
"Five times a number, n, decreased by
39 is less than twice the same number."
A)n>13
B)n< 13
C)n<-3
D)n>-3

The numerical solution to the statement is n < 13

Step-by-step explanation:

Given

Five times a number, n, decreased by 39 is less than twice the same number

Required

Find the number solution.

The first thing to do is to break the statement into bits and analyse the bits one after the other

a. Five times a number, n: This means 5 * n = 5n

b. Decreased by 39 : To decrease means, to subtract. So, we have to subtract 39 from the result in (a) above; this gives us 5n - 39

c. is less than; The term "less than" is used for comparison and it's represented mathematically by the symbol, <.

At this point, the mathematical representation of the statement is 5n - 39 <

d. twice the same number: Recall that the number is represented by letter n. So, twice the number means 2n.

To complete the statement, we have

5n - 39 < 2n.

Now, we can solve this inequality

Fist, collect like terms

5n - 2n < 39

3n < 39

Multiply both sides by ⅓

⅓ * 3n < ⅓ * 39

n < 13

Hence, the numerical solution to the statement is n < 13