A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1degreesf and a standard deviation of 0.56degreesf. construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. what does the sample suggest about the use of 98.6degreesf as the mean body temperature?

The 99% confidence interval estimate for the mean is 97.9576 ≤ μ ≤ 98.246

A) This suggests that the mean body temperature could very possibly be 98.6 °F

Step-by-step explanation:

 The number of body temperatures, n = 103

The mean body temperature, = 98.1

The standard deviation, s = 0.56

Confidence interval required = 99%

Confidence interval, CI is given by

Plugging in the values we get;

z = 2.56 at 99%

Therefore, we have

,

The statistical result suggest that at 99% confidence level, the sample mean temperature is likely to be 98.1 °F

if the pizza is divided equally into 2 equal halves then you would get

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where r is the radius of the pizza.

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