In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of the cross section be x and formed a right triangle with hypotenuse r, as shown below.

The cross-sectional area of the shaded circle is πx2. Using the Pythagorean theorem for the right triangle, we get x2 + b2 = r2. Now solve for x2 and substitute it into the area expression.

What is the result?

π(r2 – b2)
π(r2 + b2)
π(b2 – r2)
2π(b2 + r2)

30 points! i am confused. what does it mean by game time? you can use a table of random numbers or a random number generator to create random samples. also, you can obtain random samples directly using wolframalpha.com. for example, typing in randomsample[{1,2,3,4,5},2] will give you a sample of size 2 from the list {1,2,3,4,5}. a sample result is {1,5}. refreshing the page will generate a new random sample of size 2. 2. create five random samples of size two from the population. record the game times for the samples and calculate the mean game time of each sample. 3. create 5 random samples of size 11 from the population. record the game times for the samples and calculate the mean game time of each sample.

What is 0.000008 meters in scientific notation

Given right triangle a w/a hypotenuse length of x+4 and a leg of x, and right triangle b, w/ a hypotense length of 3y and a leg length of y+4 for what values of x and y are the triangles congruent by hl?