What is the Mean Absolute Deviation or MAD for each city?

City A: 4, 3.5, 5, 5.5, 4, 2

City B: 5, 6, 3.5, 5.5, 4, 6

Here are the steps to find the MAD

How to find the Mad?
The steps to find the MAD include: 1. find the mean (average). 2. find the difference between each data value and the mean. 3. take the absolute value of each difference. 4. find the mean (average) of these differences

Answer this correctly for me not the points if you answer it just for the points i will report you

5/6 and 5/6

Step-by-step explanation:

City A:

step 1: find the mean (average)

(4 + 3.5 + 5 + 5.5 + 4 + 2) / 6 = 4

step 2 and 3: find the difference between each data value and the mean AND take the absolute value of each difference

|4 - 4| = 0

|3.5 - 4| = |-0.5| = 0.5

|5 - 4| = 1

|5.5 - 4| = 1.5

|4 - 4| = 0

|2 - 4| = |-2| = 2

step 4: find the mean (average) of these differences

(0 + 0.5 + 1 + 1.5 + 0 + 2) / 6 = 5/6

City B:

step 1: find the mean (average)

(5 + 6 + 3.5 + 5.5 + 4 + 6) / 6 = 5

step 2 and 3: find the difference between each data value and the mean AND take the absolute value of each difference

|5 - 5| = 0

|6 - 5| = 1

|3.5 - 5| = |-1.5| = 1.5

|5.5 - 5| = 0.5

|4 - 5| = |-1| = 1

|6 - 5| = 1

step 4: find the mean (average) of these differences

(0 + 1 + 1.5 + 0.5 + 1 + 1) / 6 = 5/6

Hope this helps!

A: ⅚

B: ⅚

Step-by-step explanation:

City A: 4, 3.5, 5, 5.5, 4, 2

Mean: sum/n

= 24/6 = 4

|x - mean|: 0, 0.5, 1, 1.5, 0 , 2

MAD = sum|x - mean|/n

5/6 = 0.833

City B: 5, 6, 3.5, 5.5, 4, 6

Mean: 30/6 = 5

|x - mean|: 0, 1, 1.5, 0.5, 1, 1

MAD = sum|x - mean|/n

5/6 = 0.833

step-by-step explanation:

my butt

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)