The production constraints for a toy car and truck company are given by the equations of the system of inequalities.
Production Constraints:
Wheels: The company has no more than 360 wheels in stock. Each toy car needs 4 wheels, and each toy truck needs 6 wheels.
Seats: The company has no more than 100 seats in stock. Each toy car needs 2 seats, and each toy truck needs 1 seat.
x + 6y ≤ 360
2x + y ≤ 100
Which represents a viable option for the companies production of toy cars and trucks?
10 toy cars and 70 toy trucks
20 toy cars and 40 toy trucks
70 toy cars and 10 toy trucks
60 toy cars and 20 toy trucks

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!