Implicit differentiation: ycosx=x^2+y^2
derivative of both sides:
=(()+(cosx)(dy/dx)=2...
Mathematics, 25.09.2019 17:30 Lolmickles968
Implicit differentiation: ycosx=x^2+y^2
derivative of both sides:
=(()+(cosx)(dy/dx)=2x+2y(dy/dx)
=(-ysinx+cosx(dy/dx)=2x+2y(dy/dx) =cosx(dy/dx) - 2y(dy/dx) = ysinx+2x
=(cosx-2y)dy/dx = ysinx+2x
=dy/dx = (ysinx+2x)/(cosx-2y)
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