HURRY IM TIMED I GIVE BRAINLIEST
Which best describes the equation that the graph represents?

On a coordinate plane, the x-axis is labeled time (in minutes) and the y-axis is labeled distance (in kilometers). The point (5, 9) is plotted on a line that goes through (0, 0).

A; y = 0.6 x, where time is the independent variable, x, and distance is the dependent variable.

B; y = 0.6 x, where time is the dependent variable, x, and distance is the independent variable, y.

C; y = 1.8x, where time is the independent variable, x, and distance is the dependent variable.

D; y = 1.8x, where time is the dependent variable, x, and distance is the independent variable, y.
PLZ HELP IM FREAKING OUT

C

Step-by-step explanation:

Time is the independent variable, as it is x.

The slope is 9/5 = 1.8

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify