John is painting a picture. He has green, red, yellow, purple, orange, and blue paint. He wants to use four different colors on this picture. If order doesn't matter, how many ways can John pick four colors for his picture, if one of them is green?

a) .44
b) .52
c.) .23
d) .35

I'm gonna say maybe 10 yah 10

here's why

In can pick in 10 ways.

Solution:

John has green, red, yellow, purple, orange, and blue paint = total 6 colours

he wants to have 4 different colours in the painting.

But in those 4 colors green is must, it should always be there.

So except green we have total 5 colours (red, yellow, purple, orange, and blue) from which we can pick any 3 colors(as green will be one in four colours).

Then we can choose 3 colours from 5 colours in x ways.  

x ways = = \left(\frac{5 !}{3 !(5-3) !}\right)=(3!(5−3)!5!)

=\left(\frac{5 !}{3 ! \times 2 !}\right)=(3!×2!5!)

=\frac{5 \times 4 \times 3 !}{3 ! \times 2 !}=3!×2!5×4×3!

=\frac{5 \times 4}{2}=25×4

=\frac{20}{2} = 10=220=10

step-by-step explanation:

which of the following statements correctly describes the expression below based on its degree and number of terms?

314 - 7x2 + 11

answer:

what is your question that you ask

step-by-step explanation: