Two students from a group of eight boys and 12 girls are sent to represent the school in a parade if the students are chosen at random what is the probability that both students are girls?

If you choose one person from the group, you have a 12/20 chance of them being a girl. Now, if the first person is a girl, we have one less girl and one less person to choose from. So, the new probability for the second person is 11/19.

Then, we multiply the chances

12/20 * 11/19

3/5 * 11/19

33/95

be more specific

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18