The graph represents the function f(x) = 10(2)x.

On a coordinate plane, an exponential growth function approaches y = 0 in the second quadrant and goes through points (negative 1, 5), (0, 10), (1, 20), (2, 40).
How would the graph change if the b value in the equation is decreased but remains greater than 1? Check all that apply.

Step-by-step explanation:

Here you have an exponential function.  The proper format is

f(x) = 10(2)^x, where the " ^ " represents exponentiation.  

If (-1, 5) is a point on this graph, then 5 = 10(2)^1 must be true.  Then

5 = 10(2)^(-1)   =>  5 = 10/2 = 5.  This is true.

You mention a "b value" but do not show it in the equation.  Please repost this question and show b.

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.