The value of a company’s piece of equipment decreases over time due to depreciation. The function y = 16,000(0.985)2t represents the value after t years.

a.) What is the average rate of change from year 1 to year 5?

b.) What is the average rate of change from year 5 to year 10?

c.) What conclusion about the value can we make based on these average rates of change?

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A) 442

B) 385.9

C) The value is not constant. It depreciates

Step-by-step explanation:

Given the function

y = 16,000(0.985)^2t 

A) the average rate of change from year 1 to year 5 will be

When t = 1

y = 16,000(0.985)^2(1)

y = 15523.6

When t = 5

y = 16,000(0.985)^2(5)

y = 13755.69

Rate of change = (15523.6-13755.69) ÷ 4

Rate of change = 1767.91/4

Average of change = 442.0

B) the average rate of change from year 5 to year 10 will be

When t = 5

y = 16,000(0.985)^2t 

y = 16,000(0.985)^2(5)

y = 13755.69

When t = 10

y = 16,000(0.985)^2(10)

y = 11826.18

Average rate of change

= (13755.69 - 11826.18) ÷ 5

= 1929.51/2

= 385.9

C) The value is not constant. It depreciates

the answer is y = 11.54

hope this : )