Which describes the cross section of the square prism that passes through the vertices A, B, C, and D shown below?

The best option is;

A triangle with three equal sides all longer than 12 inches

Step-by-step explanation:

The cross sectional area of the square prism that passes through points A, B and C is found as follows;

Shape of cross section ABC = Triangle

Base, AB of the triangle is given by;

AB = √(8² + 8²) = √128 = 8·√2

Side, AC of the triangle is given by AC = √(8² + 12²) = 4√13

Therefore, the height of the triangle is given as follows;

Height, h = √(4·√13)²-(4·√2)² = 4·√11

The area of the cross section then is 0.5 × Base × Height

= 0.5 × 8·√2 × 4·√11  = 16·√22

A triangle with 3 equal sides of 8 inches has an area of 4×8×sin(60) = 16√3

A triangle with 2 equal sides of 12 inches and one side of 8 inches has an area of 4×12×sin(60) = 24√3

Therefore since 16·√22 > 24√3 >  16√3, the best option is a triangle with three equal sides of   all longer than 12 inches.

1,589.63 in.^3

step-by-step explanation:

i hope this you : d

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )