The longest side of an acute isosceles triangle is 8 centimeters. rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides

Let

x------> the length of one of the two congruent sides of the isosceles triangle

we know that

The Triangle Inequality Theorem states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

In this problem

the longest side is

so

Applying the triangle inequality theorem

The length of one of the two congruent sides must be greater than

A solution could be

If you round to the nearest tenth the result is equal to

therefore

the answer is

the smallest possible length is

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

no

step-by-step explanation: