I need help with my exit ticket

Slide 1 B: p=-6

Slide 2 answer : C: x=0

Slide 3 A: a=0

Step-by-step explanation:

You can do this two ways.

Way 1: plug in that answer choices to your equation and see if one of them makes the equation true

or

Way 2: isolate varable and do sadmep... reverse operations.

I will use anyone that best suits you but i will use way 2.

5p-14=8p+4

move 5p by subtracting on both sides

-14=8p-5p+4

-14=3p+4

now subtract 4 from both sides

-14-4=3p

-18=3p

now divide 3 on both sides to isolate p

-18/3=p

p=-6  

Slide 2:

for this one i will just plug in answers to see which one makes the statement correct

12=-4(-6(1)-3)

12=-4(-6-3)

12=-4(-9)

i already know its incorrect because -4*-9 is a way higher number then 12

so x=1 is incorrect

lets try x=0

12=-4(-6(0)-3)

12-4=(-6*0=0 -3)

12=-4(-3)

12=12

so x=0 is correct  

Slide 3:

For this one as well i will plug in the answers to see which one makes the statement true.

a=0

0+5=-5(0)+5

5=5

this statment is true so

a=0 is correct

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

£56

step-by-step explanation: