Mr. Kaplan bought 11 tickets to the circus and spent $50. He bought child tickets for $4 each and bought adult tickets for $7 each. How many child and adult tickets did Mr. Kaplan buy?

Mr Kaplan bought 9 child tickets and 2 adult tickets.

Step-by-step explanation:

- Mr Kaplan bought 11 tickets

- He spent $50

- Child tickets cost $4 each

- Adult tickets cost $4 each.

We want to know how many adult ticket and child ticket Mr Kaplan bought.

Better still, we want to know exactly how many $4's and $7's make $50.

Let us try out the numbers that sum up to 11.

10 + 1 = 11

9 + 2 = 11

8 + 3 = 11

7 + 4 = 11

6 + 5 = 11

Next, let us check which one(s) of these number when applied to the costs of tickets gives 50

(10×$4) + (1 × $7) = $47 ≠ $50

(10×$7) + (1×$4) = $74 ≠ 50 (10×$7, 9×$7, 8×$7, and 7×$7 are already too much, it is reasonable to ignore them)

Let's try the next one

(9×$4) + (2×$7) = $50 (This works)

Next,

(8×$4) + (3×$7) = $53 ≠ 50

(7×$4) + (4×$7) = $56 ≠ 50

(6×$5) + (5×$7) = $65 ≠ 50

So, we can conclude that Mr Kaplan bought 9 child tickets and 2 adult tickets.

angle uzt is congruent to angle tzy. angle vzw is congruent to angle yzx.

(credits to leowren)

step-by-step explanation:

over the argument its not good to fight.