How do you get 2b+8 factored?

Version one: equation is equal to 0

Given equation  

2

b

+

8

that equals zero,  

2

b

+

8

=

0

Isolate the 2b by subtracting 8 from each side  

2

b

+

8

−

8

=

0

−

8

→

2

b

=

−

8

Divide both sides by 2 to isolate b  

2

b

2

=

−

8

2

→

b

=

−

8

÷

2

=

−

4

Version two: no quantity equivalence

GIven function  

2

b

+

8

we can apply the Distributive Property

convert to proper form  

2

b

+

8

⇒

2

(

b

)

+

2

(

z

)

where  

2

z

=

8

To get variable  

z

⇒

8

÷

2

=

z

=

4

, therefore you have  

2

(

b

)

+

2

(

4

)

or in factored form,  

2

(

b

+

4

)

Step-by-step explanation:

2 (b + 4)

Step-by-step explanation:

First you rewrite 8 to be 4 times 2

2b + 2 * 4

Then you simply factor out the common term of 2

use formula for the circle a=3.14

step-by-step explanation: