What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form?
ο
x=-41 23
= 44 45
ο
ο
-4 14/3
ο
Done

x = - 4 ± 2

Step-by-step explanation:

Given

f(x) = x² + 8x + 4

To find the zeros, let f(x) = 0, that is

x² + 8x + 4 = 0 ( subtract 4 from both sides )

x² + 8x = - 4

Using the method of completing the square

add (half the coefficient of the x- term )² to both sides

x² + 2(4)x + 16 = - 4 + 16

(x + 4)² = 12 ( take the square root of both sides )

x + 4 = ± = ± 2 ( subtract 4 from both sides )

x = - 4 ± 2

what is the original number? you forgot to add it.