A model rocket is launched from a roof into a large field. The path of the rocket can be
modeled by the equation y = -0.04x2+ 5.8x + 4.9, where x is the horizontal distance, in
meters, from the starting point on the roof and y is the height, in meters, of the rocket
above the ground. How far horizontally from its starting point will the rocket land?

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8