You have two ways to drive home from school: Route A is usually quicker; Route B is
scenic but slower. You choose Route A on 60% of your days and this gets you home by
4:00 P. M. 80% of the time. When you choose Route B you get home by 4:00 P. M. only
30% of the time. What is the probability that you choose Route B and get home by 6:00
P. M.?

0.12 = 12%

Step-by-step explanation:

To find this probability, we need to multiply the probability of getting route B, and the probability of getting home by 4 P.M if we choose route B.

If the probability of choosing route A is 60%, we have that the probability of choosing route B is 100% - 60% = 40%

Then, we have that the probability of getting home by 4 P.M. when choosing route B is 30%, so the final probability is:

P = 40% * 30% = 0.4 * 0.3 = 0.12 = 12%

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

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