I need help please! I'm stumped and I don't know what to do.

Here,

3y-49=0(i)

x^2+y^2-281=0(ii)

from eqn (i)

y=49/3

Now,substituting value of y in eqn (ii)

x^2+(49/3)^2-281=0

or,x^2+2401/9-281=0

or,9x^2+2401-2529=9×0

or,9x^2=128

or,x^2=128/9

therefore,

x=8√2/3

Hope it helps...

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .