Quadrilateral ABCD is inscribed in circle O.

What is m∠C ?

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°

A quadrilateral is inscribed in a circle O. The vertices of the quadrilateral lie on the edge of the circle and are labeled as A, B, C, and D. The interior angle B is labeled as 2 x plus 3. The interior angle C is labeled as 2 x plus 1. The interior angle D is labeled as 4 x plus 3.

Opposite angles of inscribed quadrilaterals are supplementary.

That means ∠D + ∠B = 180°

So, we can substitute in the given values.

(4x + 3) + (2x + 3) = 180

Solve for x.

4x + 3 + 2x + 3 = 180

6x + 6 = 180

6x = 174

x = 29

We know ∠C = 2x + 1, so we can substitute our value of x in.

∠C = 2x + 1

∠C = 2 * 29 + 1

∠C = 58 + 1

∠C = 59°

my answer is$ 12

step-by-step explanation:

because 15 -2=12

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: