In circle A, ∠BAE ≅ ∠DAE.

Circle A is shown. Line segments A B, A E, and A D are radii. Lines are drawn from point B to point E and from point E to point D to form secants B E and E D. Angles B A E and E A D are congruent. The length of B E is 3 x minus 24 and the length of E D is x + 10.

What is the value of x?

14
17
27
34

The image of circle A is missing, so i have attached it;

x = 17

Step-by-step explanation:

In Δs EAB and EAD

We are told that;

∠BAE ≅ ∠DAE

AB = AD = AE

Now,

The Two triangles have two corresponding equal sides and the angles between them are equal, thus, we can say that the two triangles are congruent by SAS (Side Angle Side) postulate of congruence

By using the result of congruence, we can say that;

EB ≅ ED

We are given that;

EB = 3x - 24 and ED = x + 10

Thus,

3x - 24 = x + 10

∴ 3 x - 24 = x + 10

Add 24 to both sides to give;

3x = x + 34

Subtract x from both sides to give;

2x = 34

Divide both sides by 2 to give;

x = 17

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36