A helicopter flying 1600 feet above the ground spots an airplane flying above. If the hortizontal distance between the helicopter and airplane is 3055 feet and the angle of elevation is 71 degress

Question:

A helicopter flying 1,600 feet above the ground spots an airplane flying above. If the horizontal distance between the helicopter and airplane is 3,055 feet and the angle of elevation is 71°, find the airplane’s altitude.

The airplane altitude is 10472.364 ft

Step-by-step explanation:

The question is related to an angle of elevation problem which we answer as follows;

Altitude of flying helicopter = 1600 ft

Angle of elevation of airplane = 71 °

Horizontal distance between helicopter and airplane = 3055 ft

The vertical distance between the helicopter and the airplane is thus;

Where the angle is 71 ° as in the question, we have;

∴ Vertical distance between airplane and helicopter = tan71° × 3055

= 8872.364 ft.

The altitude of the airplane is then;

Altitude of the helicopter + 8872.364 ft

= 1600 + 8872.364  = 10472.364 ft

The airplane altitude = 10472.364 ft.

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.