What is the y-intercept of the equation of the line that is perpendicular to the line y=x + 10 and passes through the point
(15,-5)?

how am i supposed to answer

step-by-step explanation:

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen